Math, asked by malleshamburra6, 7 months ago

The point 'B' is the image of 'A' in the line x+y+4=0x+y+4=0 and 'C' is the image of 'B' in the line 2 x-y+7=0,2x−y+7=0, if A=(1,6)A=(1,6) then the circumcentre of the triangle \mathrm{ABC}ABC is​

Answers

Answered by praful22979
4

Step-by-step explanation:

ANSWER

5x+3y−2=0

(3x−y−4=0)×3

14x−10=0

x=

7

5

7

5

+3y−2=0

3y+

7

−14+15

=0

3y=

7

−1

⇒y=−1/21

P(

7

5

,

21

−1

)

Similarity x−y+1=0

2

x−

+

y

+

2

=0

−x+1=0,x=1 and y=2

Q(I,2)

equation of line passing through P & Q

5x+3y02=0

3x−y−4=0)×3

14x−14=0

x=1

y=−1

P(I,−)

2X−Y−2=0

x

+

y

1

=0

x−3=0

x=3

y=4

Q(3,4)

Equation of line PQ

y+1=

3−1

4+1

(x−1)

y+1=

2

5

(x−1)

2y+2=5x−5

5x−2y−7=0

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