Question

the point equidistant from the point(0, 0), (2, 0) and(0, 2) is​

Answer 1

Answer:

Let P(x,y) is equidistant from the points A(0,0),B(2,0) and C(0,2).

So. PA=PB=PC

Using the distance formula we get,

PA=

x

2

+y

2

PB=

(x−2)

2

+y

2

PC=

x

2

+(y−2)

2

∵PA=PB

Squaring both sides. ⇒PA

2

=PB

2

⇒x

2

+y

2

=(x−2)

2

+y

2

⇒x

2

=x

2

+4−4x

⇒4x=4

⇒x=1

Again PA=PC

Squaring both sides. ⇒PA

2

=PC

2

⇒x

2

+y

2

=x

2

+(y−2)

2

⇒y

2

=y

2

+4−4y

⇒4y=4

⇒y=1

Here, required point is (1,1)

please brainliest mark