Question

the point from where a ball is projected is taken as the origin of the coordinate axes. the x and y components of its displacement are given by x=6t and y= 8t-5t*2​

Answer 1

Answer:

X=6t

【t=x/6】--------1

Put the value of t in y

【Y=8x/6 - 5x^2/36】-------2

Or equation of trajectory..

Now, the time of flight at final point wher y=0.

Put y=0 in eq y=8t-5t^2

U will get, 【t=8/5 secs】

Now, Range will be also at (final point, 0)

So put y=0 in eq 2

U will get,

X or range=48/5

And range = u^2sin2theta/g

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Do maths yourself

.. put variables in formula of time of flight u will het usintheta =8

Now put usintheta in formula of range u will get ucosteta =6

Now if u know how to calculate velocity than do it on your own..

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U=10 m/sec

Hope it helps.

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Answer 2

Answer:

u get the.

u=10 m/sec

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