Question

the point (k, 2-2k), (1-k, 2k) , (-4-k,6-2k) are collinear the k =?

Answer 1

hey,

here ur answer

if points are collinear then area of triangle is always zero

area of triangle = 1/2 [x1 (y2-y3) + x2(y3-y1) + x3(y1-y2)]

by applying formula u will get the value of k.