Question

The point of application of a force
F=5i - 3j+2k is moved from fi =2i+7)+21
to i=-5i+2j+3k. The work done will be
1) +22 units 2) -18 units
3) 11 units 4) -11 units​

Answer 1

Answer:

Explanation:

work=force*displacement

Answer 2

The work done will be (-56 joules).

Explanation:

Force, F = 5i-3j+2k

Initial position, x = 2i+7j+21k

Final position, x' = -5i+2j+3k

Displacement : $x'-x=-5i+2j+3k-(2i+7j+21k)=-7i-5j-18k$

The work done by the force is given by :

$W=F{\cdot}(x'-x)\\\\W=(5i-3j+2k)(-7i-5j-18k)\\\\W=-35+15-36$

W = -56 Joules

So, the work done will be (-56 joules).

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Work done

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