The point of intersection of linear
equations x + y = 4 and x + 2y = 8
Answers
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1
Answer :
(0 , 4)
Solution :
Here ,
The given linear equations are ;
x + y = 4 -------(1)
x + 2y = 8 --------(2)
Now ,
Subtracting eq-(1) from (2) , we get ;
=> (x + 2y) - (x + y) = 8 - 4
=> x + 2y - x - y = 4
=> y = 4
Now ,
Putting y = 4 in eq-(1) , we get ;
=> x + y = 4
=> x + 4 = 4
=> x = 4 - 4
=> x = 0
Hence ,
The required point is (0 , 4) .
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