Question

The point of intersection of the latus rectum and axes of the parabola y^2+4x+2y-8=0 is

Answer 1

Answer:

(5/4,-1)

Step-by-step explanation:

The point of intersetion of latus rectum and the axes of parabola is focus of parabola,

S(h-a,k) ,where S is the focus

Answer 2

Answer:

(5/4,-1)

Step-by-step explanation:

y^2+4x+2y-8=0

(y+1)^2=-4(x-9/4)

on comparing with (y-k)^2=4a(x-h)

then,

a=-1 ,h=9/4 ,k=-1

y=k i.e, y=-1

x=a+h

x=-1+9/4=5/4

(5/4,-1)