Question

the point of intersection of the straight line px+qy=r(q#0) with the y-axis is​

Answer 1

Answer:

hey friend here is your answer

A point on y-axis have x-coordinate = 0

so for finding intersection point on y-axis put x=0 in equation of straight line.

so put x=0 in px+qy = r

by putting it, we get

qy = r

y = r/q.

hence point of intersection is (0, r/q).

So your final answer is (0, r/q).

I hope you get your answer

thanks for asking

please mark as brainlist...

Answer 2

Step-by-step explanation:

Given:

$px + qy = r \: (q \neq0)$

To find: The point of intersection of the given straight line with the y-axis is ?

Solution:

Tip: On y-axis, x coordinate is zero.

Step 1: Put x=0 in the equation

$p(0) + qy = r$

or

$qy = r$

Step 2: Take q in RHS by cross multiplication

$y = \frac{r}{q}$

Step 3: Write the point of intersection.

Point of intersection is (0,r/q)

Final answer:

The point of intersection of the given straight line with the y-axis is (0,r/q).

Hope it helps you.

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