Question

the point of the line 3x+4y=5 which is equidistance from (1,2) and (3,4)

Answer 1

Answer:

(15, -10)

Step-by-step explanation:

3x + 4y = 5 ==> y = $\frac{-3x+5}{4}$

Any point on the given line has coordinates

(x, $\frac{-3x+5}{4}$ )  

at this point, please see attachments