Math, asked by satveer2410a, 6 months ago

The point on the curve x^2= 2y which is nearest to the point (0,5) is
(A) (272,4)
(B) (2/2,0) (C) (0,0)
(D) (2, 2)

Explain.

Answers

Answered by pc955392

0

Answer:

option B is the correct answer for your question

Step-by-step explanation:

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