Math, asked by siddhu7718, 10 months ago

The point on the curve x^2 = 2y which is nearest to the point (0, 5) is

A. (2√2,4)
B. (2√2,0)
C. (0, 0)
D. (2, 2)

Answers

Answered by DevanshP

1

Answer:

a

Step-by-step explanation:

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