Question

The point on the curve y equal to 12x-x square where the slope of the tangent is 0 will be ?

Answer 1

Answer:

0

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

Let the point be P(x,y)

y=12x−x^2

(dy/dx) = 12−2(x1)

(x1,y1)

since slope of tangent is zero

so ( dy/dx) =0

(x1,y1)

12−2(x1) =0

2(x1) =12

(x1) = 6

Also curve passing through tangent

(y1) =12(x1) - (x1)^2

(y1) =12×6−36

(y1) =72−36

(y1) =36

So, The points are (6,36).

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