Question

the point on the curve y = x ^2 -3x +2 where tangent is perpendicular to y = x​

Answer 1

Answer:

I hope it is hopefull for you

Step-by-step explanation:

If the tangent lines are perpendicular to

x

=

1

they are parallel to x-axis. Slope of the x-axis is equal to zero and every line parallel with x-axis has the same slope, so

k

=

0

.

k

=

y

'

=

−

4

x

3

+

16

x

=

0

−

4

x

(

x

2

−

4

)

=

0

⇔

x

=

0

∨

x

2

−

4

=

0

x

=

0

∨

x

=

−

2

∨

x

=

+

2

y

(

0

)

=

0

⇒

y

=

0

y

(

−

2

)

=

16

⇒

y

=

16

y

(

+

2

)

=

16

⇒

y

=

16

So, tangents are:

y

=

0

∧

y

=

16