the point on the graph of linear equations 4x+7y=21 whose ordinate is 5/3 times it's abscissa is
Answers
Given :- the point on the graph of linear equations 4x+7y=21 whose ordinate is 5/3 times it's abscissa is ?
Solution :-
we know that,
- Abscissa = x - axis point .
- ordinate = y - axis point .
given that,
→ y = (5/3) * x
putting value of y in given linear equations 4x+7y=21 ,
→ 4x + 7y = 21
→ 4x + 7(5x/3) = 21
→ 4x + (35x/3) = 21
→ (12x + 35x)/3 = 21
→ (47x/3) = 21
→ 47x = 63
→ x = (63/47)
then,
→ y = (5/3)x
→ y = (5/3) * (63/47)
→ y = (105/47)
therefore, the required point is (63/47, 105/47) .
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Given : the point on the graph of linear equations 4x+7y=21 whose ordinate is 5/3 times it's abscissa
To Find : Point
Solution:
linear equations 4x+7y=21
=> 7y = 21 - 4x
=> y = 3 - 4x/7
abscissa is x coordinate
ordinate is y coordinate
=> y = 5x/3
Equate both
=>5x/3 = 3 - 4x/7
=> 5x/3 + 4x/7 = 3
=> 35x + 12x = 63
=> 47x = 63
=> x = 63/47
y = 5x/3 (5/3)(63/47) = 105/47
Point is ( 63/47 , 105/47 )
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