Question

The point on the x-axis which is eqidistance from (-4,0) (10,0) find the answer

Answer 1

intersection between 4x+2y=7 and y-axis i.e. x=0

put x=0 in 4x+2y=7

y=7/2

hence point of inersection is (0,7/2)

now unknown equation parellel to

y-7x+5=0

slope of unknown line =slope of above line =7

now equation of line

(y-7/2)=7 (x-0)

7x-y+7/2=0

14

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