Question

The point on the x-axis which is equidistant from (2, - 5) and (- 2, 9) is (- 7, 0).

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Answer 1

Step-by-step explanation:

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Answer 2

Answer:

To find the distance between P and B, substitute the values of P (x, 0) and B (- 2, 9) in the distance formula. By the given condition, these distances are equal in measure. Therefore, the point equidistant from the given points on the x-axis is (- 7, 0).

Step-by-step explanation:

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