Question

The point on the x-axis which is equidistant from (-4,0) and (10, 0) is

Answer 1

Answer:

Step-by-step explanation:

Let P(x,y) be the equidistant point between A(-4,0) and B(10,0).

P(x,y) = (x₁ + x₂/2 , y₁ + y₂/2)                            (x₁ = -4 , y₁ = 0

         = (-4 + 10/2 , 0 + 0/2)                             x₂ = 10 , y₂ = 0)

         = (6/2 , 0)

         = (3,0)

∴ P(x,y) =  P(3,0)