The point on the x axis which is equidistant from the points (-1,0) and (5,0) is
(0,2)
(2,0)
(0,0)
(3,0)
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Since point lies on x-axis, y-coordinate of the point will be zero.
Let P(x,0) be on x-axis which is equidistant from A(−1,0) and B(5,0)
Using section formula:
x=
1+1
1×(5)+1×(−1)/1-1
or x=2
Thus, the required point is (2,0).
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