The point on the x-axis which is equidistant from the points A(-2, 3) and B(5, 4) is
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Let P(x, 0) be a point on X-axis such that AP=BP
⇒AP
2
=BP
2
⇒(x+2)
2
+(0−3)
2
=(x−5)
2
+(0−4)
2
⇒x
2
+4x+4+9⇒x
2
−10x+25+16
⇒14x=28⇒x=2
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