Question

The point on x-axis which divides the line segment joining (2,3) and (6,-9) in the ratio 1:3 is

Answer 1

Step-by-step explanation:

if it divides internally then use the formula

$x = (m1x2 + \: m2x1) \div (m1 + m2)$

and

$y =( m1y2 + m2y1) \div (m1 + m2)$

here x1=2:

x2=6:

y1=3:

y2= -9

m1=1:

m2=3:

by putting these values in the given formula u will gey the ans as x=3

y=0

hope it helped.

Answer 2

6*1+3*2/4=3

1*-9+3*3/4=0

so x =3 and y =0