Question

The point on x-axis which is equidistance from (2, -5) and (-2, 9) are *

​

Answer 1

Answer:

The point is on X axis

so the value of y is 0

= so the point are (X,0)

So by distance formula

• distance between (x,0),(2,-5)and(x,0),(-2,9)is equal
• so by solving it we get
• -4x-4x=81-25
• -8x=81-25
• -8x=56
• x=56/-8
• x=-7

so the points are (-7,0)