Question

the point on x axis which is equidistant from the point (6,2) and (5,4) is

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Answer 1

Step-by-step explanation:

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Answer 2

Answer:Let the point on the x−axis be P(a,0)

Let the other two point be A(6,2) and B(5,4)

So by distance formula we have,

Distance between two points =  

root (x2-x1)^2 + (y2-y1)^2

Then,

PA=PB

PA ^2 =PB^2  

⇒(a-6)  ^2+(0-2) ^2 =(a−5)^2 +(0-4)^2  

⇒a^2  +36+12a+4=a  ^2+25+10a+16

⇒12a+40=10a+41

⇒ 2a=1⇒a=0.5

∴ The required point isP(0.5,0)