Question

The point on y axis equidistant from (-3,4) and (7,6) is

Answer 1

Answer:

Step-by-step explanation:

Given points

 A(7,6) and B(-3,4)

Let the point be P(0,y)  [we know that point on y-axis is (0,y)]

So, AP=PB and AP² = PB² 

⇒(y-7)²+(0-6)²=(y+3)²+(0-4)²

y²+49-14y + 36= y²+9+6y + 16

49-9+36-16=6y + 14y

40+20=20y

60/20=y

⇒y=3

Hence, point on x-axis which is equidistant from the points A(7,6) and B(-3,4) is (0,3).-----Ans.

HOPE THIS WILL HELP YOU.......

Answer 2

Answer:

(0,15)

Step-by-step explanation:

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