The point on Y-axis which is equidistant from (6,-1) and (2,3) is
a) (0,-1)
b) (0,1)
c) (0,-3)
d) (0,3)
Answers
Answered by
2
Answer:
option number b is the correct optiin
Answered by
15
Answer:
(c)(0,-3)
Step-by-step explanation:
let the coordinates of point on Y axis which is equidistant from (6,-1) &(2,3) is (0,y)
now by using distance formula we get
√(6-0)^2 + (-1-y)^2 = √(2-0)^2 + (3-y)^2
36 +1+y^2+2y= 4 + 9 +y^2 - 6y
8y = -24
y = -3
coordinates are (0,-3)
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