Question

the point on y-axis which is equidistant from(6-1)and(2,3)is ans
pls explain step by step ans i want​

Answer 1

Answer:

(c)(0,-3)

Step-by-step explanation:

let the coordinates of point on Y axis which is equidistant from (6,-1) &(2,3) is (0,y)

now by using distance formula we get

√(6-0)^2 + (-1-y)^2 = √(2-0)^2 + (3-y)^2

36 +1+y^2+2y= 4 + 9 +y^2 - 6y

8y = -24

y = -3

coordinates are (0,-3)

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