The Point on Z axis which are at a distance of 6 units from the point (-4,2,-1) are
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Step-by-step explanation:
Let the point on Z axis be given as (0,0,z). The distance between (1,2,3) and (0,0,z) is given as
1
2
+2
2
+(3−z)
2
=
21
5+(3−z)
2
=21
z
2
−6z−7=0
z=7,z=−1
Hence points are (0,0,7),(0,0,−1)
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