the point p and q are mid point of side AB and side AC respectively in triangle ABC if BC=2.8cm then PQ=
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Answer:
If a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct points, the other two sides are divided in the same ratio.
Hence
QC
AQ
=
PB
AP
3
2
=
PB
2.4
PB=3.6cm
AB=AP+PB=2.4+3.6=6cm
As PQ∥BC
∠AQP=∠ACB
∠APQ=∠ABC
So by AAA △AQP∼△ACB
Hence
AC
AQ
=
CB
QP
5
2
=
6
QP
QP=2.4cm
So AB=6cm and QP=2.4cm
Step-by-step explanation:
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