Question

the point p divides the segment ab joining points a(2 1) and B(-3, -6) thus point p lie on the line x-5y+15=0​

Answer 1

Answer:We have,

ABAP=31= AP+PBAP=31→ 3AP=AP+BP

→ 2AP=BP

BPAP=21

So, P divides AB in the ratio 1:2.

:Coordinates of Pure(1+21x5+2x2,1+21x-8+2x1)

=(3,2)

Since,P(3,2) lies on the line 2x-y+k=0.

.:2*3-2+k=0 → k=-4

TYPE III ON DETERMINATION OF THE TYPE OF A GIVEN QUADRILATERAL

Step-by-step explanation: