Question

The point P on the parabola y = 4ax
for which (PR-PQ) is maximum,
where R=(-a,0), Q = (o,a) is.​

Answer 1

Answer:

Explanation:

The point on parabola y  

2

=4ax for which (PR.PQ) is maximum where R(−a,0),Q(0,a) is :

(0,a) lie outside parabola  

(PR−PQ) is maximum is PQR is at line  

Slope of PQ= slope of PR

Let  

P=(at  

2

,2at)

at  

2

 

2at−a

​  

=  

at  

2

+a

2at

​  

 

t  

2

 

2t−1

​  

=  

t  

2

+1

2t

​  

 

(t−1)  

2

=0

t=1

P=(a,2a)