Question

The point P on X-axis equidistant from the points A(-1,0)&B(5,0) is

Answer 1

Answer:

(a) P(2,0)

Explanation:

let the co ordinates of the point p be (x,0)

Now, according to the question

PA = PB

theredore by distance formula

root of (x+ 1)^2 = root of ( x - 5) ^2

squaring both side we get

x ^2 + 2x + 1 = x^2 - 10x + 25

2x + 10x = 25 - 1

12x = 24

so x = 2

so the coordinates of P are (2,0)

i hope this will help you.

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