Math, asked by nhgbgn, 8 months ago


The point P on x-axis equidistant from the points
A(-1,0) and B(5,0) is
(a) (2,0)
(b) (0, 2)
(c) (3,0)
(d) (2, 2)​

Answers

Answered by niludevi375
61

Answer:

answer is (2,0)

hope it will help u

Answered by pinquancaro
102

Option a - (2,0)

Step-by-step explanation:

Given : The point P on x-axis equidistant from the points  A(-1,0) and B(5,0).

To find : What is the point ?

Solution :

As the point is on x-axis the y-coordinate is zero i.e. P=(x,0)

Now, Point P is equidistant from A(-1,0) and B(5,0) so distance is same.

i.e. AP=PB

Applying distance formula, d=\sqrt{(x_2-x_1)^2+(y_2-y-1)^2}

\sqrt{(x-(-1))^2+(0-0)^2}=\sqrt{(5-x)^2+(0-0)^2}

\sqrt{(x+1)^2}=\sqrt{(5-x)^2}

x+1=5-x

2x=4

x=2

Therefore, the point is P=(2,0).

So, Option a is correct.

#Learn more

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