The point P on x-axis equidistant from the points A(-1,0) and B(5, 0) is(a) (2,0)(b) (0, 2)(c) (3, 0) (d) (2, 2)
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Answer:
a) (2,0)
Step-by-step explanation:
P(x,0) as it lies on x-axis
PA = PB
square on both sides
(PA)² = (PB)²
(x+1)² +(0+0)² = (x-5)² +(0+0)²
x² +2x +1 = x² -10x +25
x²- x² +2x +10x =25 - 1
12x = 24
x = 2
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