Question

The point (p, q) is equidistant from (3, 6) and (-3, 4). The relation between p and q is :
a) p + 3q = 5
b) 3p + q = 5
c) 3p - q = 5
d) p - 3q = 5

Answer 1

In the attachment I have answered this problem.

I have applied distance formula to find the distance between the given two points in the problem.

I hope this answer helps you

Answer 2

Solution:-

given by:-

The point (p, q) is equidistant from (3, 6) and (-3, 4).

by formula

$d = \sqrt{ {(x2 - x1)}^{2} + {(y2 - y1)}^{2} }$
given point (p,q) and (3.6) = (p,q) and (-3,4)

$\sqrt{ {(3 - p)}^{2} + {(6 - q)}^{2} } = \sqrt{ {( - 3 - p)}^{2} + {(4 - q)}^{2} } \\ squaring \: at \: both \: side \\ 9 + {p}^{2} - 6p + 36 + {q}^{2} - 12q = 9 + {p}^{2} + 6p + 16 + {q}^{2} - 8q \\ - 6p - 6p - 12q + 8q = 16 - 36 \\ - 12p - 4q = - 20 \\ - 3p - q = - 5\\ (3p + q = 5)ans$

your option( B) 3p+q=5 is right

☆i hope its help☆