the point Q(-3,-2)lies on a line parallel to the y-axis write the equation of the line.
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Answered by
1
Answer:
x = -3
Step-by-step explanation:
Because slope for y-axis in undefined so y term won't be present
Answered by
2
The equation of a line parallel to y-axis and passing through the point Q(-3, -2) is x = -3
Solution:
The equation of line parallel to y axis is given as:
x = k
Where, "k" is the x co-ordinate of line
Given that,
The line parallel to y-axis and passing through the point Q(-3, -2)
Therefore,
Equation of line is given as:
x = -3
In standard form,
x + 3 = 0
Thus the equation of line is found
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