Question

the point Q(-3,-2)lies on a line parallel to the y-axis write the equation of the line.​

Answer 1

Answer:

x = -3

Step-by-step explanation:

Because slope for y-axis in undefined so y term won't be present

Answer 2

The equation of a line parallel to y-axis and passing through the point Q(-3, -2) is x = -3

Solution:

The equation of line parallel to y axis is given as:

x = k

Where, "k" is the x co-ordinate of line

Given that,

The line parallel to y-axis and passing through the point Q(-3, -2)

Therefore,

Equation of line is given as:

x = -3

In standard form,

x + 3 = 0

Thus the equation of line is found

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The point Q( -3,-2) lies on a line parallel to the Y-axis. Write the equation of the line and draw its graph.

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