Question

The point-slope form of the equation of a line that passes through points (8, 4) and (0, 2) is y – 4 = y minus 4 equals StartFraction one-fourth EndFraction left-parenthesis x minus 9 right-parenthesis.(x – 8). What is the slope-intercept form of the equation for this line?

Answer 1

Answer:

GIVEN :

The point-slope form of the equation of the line that passes through (-4, -3) and (12, 1) is y minus 1 equals Start Fraction one-fourth End Fraction left-parenthesis x minus 12 right-parenthesis.

Step-by-step explanation:

TO FIND :

The standard form of the equation for this given line

SOLUTION :

Given points (-4, -3) and (12, 1) are passes through the given line is

The Standard form of the line equation is

ax+by=c

Solve the line equation y-1=\frac{1}{4}(x-12)

4(y-1)=x-12

4y-4=x-12

x-12-4y+4=0

x-4y-8=0

x-4y=8

∴ the standard form of the equation for this given line is x-4y=8

hope it helps

mrk me as BRAINLIEST