Question

The point-slope form of the equation of the line that passes through (–4, –3) and (12, 1) is y – 1 = y minus 1 equals StartFraction one-fourth EndFraction left-parenthesis x minus 12 right-parenthesis.(x – 12). What is the standard form of the equation for this line?

Answer 1

GIVEN :

The point-slope form of the equation of the line that passes through (-4, -3) and (12, 1) is y minus 1 equals Start Fraction one-fourth End Fraction left-parenthesis x minus 12 right-parenthesis.

TO FIND :

The standard form of the equation for this given line

SOLUTION :

Given points (-4, -3) and (12, 1) are passes through the given line is $y-1=\frac{1}{4}(x-12)$

The Standard form of the line equation is

ax+by=c

Solve the line equation $y-1=\frac{1}{4}(x-12)$

$4(y-1)=x-12$

4y-4=x-12

x-12-4y+4=0

x-4y-8=0

x-4y=8

∴ the standard form of the equation for this given line is x-4y=8

Answer 2

Answer:

x – 4y = 8

Step-by-step explanation:

i got the answer after the quiz :)