The point-slope form of the equation of the line that passes through (–9, –2) and (1, 3) is y – 3 = one-half EndFraction(x – 1). What is the slope-intercept form of the equation for this line?
Answers
Answered by
3
Answer:
Step-by-step explanation:
the point-slope form of the equation of the line that passes through (-4, -3) and (12, 1) is y minus 1 equals Start Fraction one-fourth End Fraction left-parenthesis x minus 12 right-parenthesis.
The standard form of the equation for this given line
SOLUTION :
Given points (-4, -3) and (12, 1) are passes through the given line is
The Standard form of the line equation is
ax+by=c
Solve the line equation y-1=\frac{1}{4}(x-12)
4(y-1)=x-12
4y-4=x-12
x-12-4y+4=0
x-4y-8=0
x-4y=8
∴ the standard form of the equation for this given line is x-4y=8
Answered by
12
Answer:
Hope this will help
Step-by-step explanation:
Attachments:
Similar questions