The point where normal to y=x²-2x+3 is parailel to Y-axis is ......,Select correct option from the given options.
(a) (0,3)
(b) (-1,2)
(c) (1,2)
(d) (3,6)
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answer : option (c)
explanation : we have to find the point where normal to y = x² - 2x + 3 is parallel to Y-axis.
first differentiate equation of curve with respect to x,
i.e., dy/dx = 2x - 2
hence, slope of tangent ⇒dy/dx = 2x - 2
we know, normal to the curve is perpendicular on tangent to the curve.
so, slope of normal × slope of tangent = -1
or, slope of normal = -1/(2x - 2).....(1)
a/c to question,
normal is parallel to Y-axis.
slope of Y-axis = 1/0
so, slope of Y-axis = slope of normal
or, 1/0 = -1/(2x - 2)
or, 2x - 2 = 0
or, x = 1 putting in equation, y = x² - 2x + 3
so, y = (1)² - 2(1) + 3 = 2
hence, required point : (1,2)
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