Question

The point which divides the join of the points (7, -6) and (3, 4) in the ratio 1:2
lies in
the ......... quadrant.​

Answer 1

SOLUTION:-

Given points:

⚫A= (7,-6)

⚫B =(3,4)

Therefore,

If a point P(x,y) divides the line AB joining the points A(x1,y1) & B(x2,y2) in the ratio m:n internally, then coordinates of point P are given by

$x = \frac{mx2 + nx1}{m + n} \: ,\: y = \frac{my2 + ny1}{m + n} \\ \\ = > \frac{1 \times 3 + 2 \times 7}{1 + 2} , \: \frac{1 \times 4 + 2 \times (- 6)}{1 + 2} \\ \\ = > \frac{3 + 14}{3} , \: \frac{4 + ( - 12)}{3} \\ \\ = > (\frac{17}{3} , \: \frac{4 - 12}{3} ) \\ \\ = >( \frac{17}{3} , \frac{ - 8}{3} )$

Hope it helps ☺️