Question

The point which is equidistant from(0,0),(0,8),(4,6) is

Answer 1

Answer:

answer

Let the point (x,y,z)(x,y,z) be the equidistant from (a,0,0), (0,b,0), (0,0,c)(a,0,0),(0,b,0),(0,0,c) and (0,0,0)(0,0,0).

\Rightarrow (x-a)^2+(y-0)^2+(z-0)^2=(x-0)^2+(y-b)^2+(z-0)^2⇒(x−a)

2

+(y−0)

2

+(z−0)

2

=(x−0)

2

+(y−b)

2

+(z−0)

2

=(x-0)^2+(y-0)^2+(z-c)^2=(x-0)^2+(y-0)^2+(z-0)^2=(x−0)

2

+(y−0)

2

+(z−c)

2

=(x−0)

2

+(y−0)

2

+(z−0)

2

Solving above equations, we get x=\dfrac{a}{2}, y=\dfrac{b}{2}, z=\dfrac{c}{2}x=

2

a

,y=

2

b