The point which is equidistant to the points (9, 3),
(7, -1) ,(-1,3)
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Answered by
8
Answer:
( 4 , 3) is equidistant to the points (9, 3), (7, -1) ,(-1,3)
Step-by-step explanation:
The point which is equidistant to the points (9, 3),
(7, -1) ,(-1,3)
Let say Point (x , y)
the distance
= √(x -9)² + (y-3)² = √ (x - 7)² + (y + 1)² = √(x + 1)² + (y -3)²
√(x -9)² + (y-3)² = √(x + 1)² + (y -3)²
=> (x -9)² + (y-3)² = (x + 1)² + (y -3)²
=> (x -9)² = (x + 1)²
=> x² - 18x + 81 = x² + 1 + 2x
=> 20x = 80
=> x = 4
√ (x - 7)² + (y + 1)² = √(x + 1)² + (y -3)²
=> (x - 7)² + (y + 1)² = (x + 1)² + (y -3)²
putting x = 4
=> (4-7)² + (y + 1)² = (4 + 1)² + (y -3)²
=> 9 + y² + 1 + 2y = 25 + y² + 9 - 6y
=> 8y = 24
=> y = 3
( 4 , 3) is equidistant to the points (9, 3), (7, -1) ,(-1,3)
Answered by
1
Answer:
(4,3) is the answer
Step-by-step explanation:
hope it helps..
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