Math, asked by aashritha6617, 11 months ago

The point which is equidistant to the points (9, 3),
(7, -1) ,(-1,3)​

Answers

Answered by amitnrw
8

Answer:

( 4 , 3)  is equidistant to the points (9, 3), (7, -1) ,(-1,3)​

Step-by-step explanation:

The point which is equidistant to the points (9, 3),

(7, -1) ,(-1,3)​

Let say Point (x , y)

the distance

= √(x -9)² + (y-3)²   = √ (x - 7)² + (y + 1)²  = √(x + 1)² + (y -3)²

√(x -9)² + (y-3)²  = √(x + 1)² + (y -3)²

=> (x -9)² + (y-3)² = (x + 1)² + (y -3)²

=>  (x -9)² =  (x + 1)²

=> x² - 18x + 81 = x² + 1 + 2x

=> 20x = 80

=> x = 4

√ (x - 7)² + (y + 1)²  = √(x + 1)² + (y -3)²

=> (x - 7)² + (y + 1)² = (x + 1)² + (y -3)²

putting x = 4

=> (4-7)² + (y + 1)² = (4 + 1)² + (y -3)²

=> 9 + y² + 1 + 2y = 25 + y² + 9 - 6y

=> 8y = 24

=> y = 3

( 4 , 3)  is equidistant to the points (9, 3), (7, -1) ,(-1,3)​

Answered by sujasujab3
1

Answer:

(4,3) is the answer

Step-by-step explanation:

hope it helps..

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