Question

The Point which lies on the perpendicular bisector of the line segment joining the points P(-3,2) and B(11,-8) is​

Answer 1

Step-by-step explanation:

sorry bhaia I also don't no but I am trying to make it please mark me as brainleist and please follow me and please mark my answers as brainleist please I need

Answer 2

Answer:

Step-by-step explanation:

Midpoint M of the segment PB is

$M(\frac{x_{1}+x_{2}}{2} ,\frac{y_{1}+y_{2}}{2}) = M(\frac{-3+11}{2},\frac{2-8}{2})$ = M(4, -3)

Slope "m" of line passing through points P and B is

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} = \frac{-8-2}{11+3} = -\frac{5}{7}$

y + 3 = $-\frac{5}{7}$(x - 4)

$y=-\frac{5}{7}x- \frac{1}{7}$

Slope of the line perpendicular to line $y=-\frac{5}{7}x- \frac{1}{7}$ is opposite reciprocal to $-\frac{5}{7}$ ; $m = \frac{7}{5}$ and equation $y=\frac{7}{5}x-\frac{43}{5}$

Any point which lies on the perpendicular bisector satisfies the equation

$y=\frac{7}{5}x-\frac{43}{5}$