Question

The point whose abscissa is equal to its ordinate and which is equidistant from A(5,0) and B(0,3) is​

Answer 1

Answer:

The required co-ordinates of the point are (1, 1). Step-by-step explanation: Given that a point with equal ordinate and abscissa is equidistant from the points A(5, 0) and B(0, 3).

Step-by-step explanation:

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Answer 2

Answer:

Step-by-step explanation:

Given:

Point P which is having its  abscissa equal to its ordinate and which is equidistant from A(5,0) and B(0,3)

To find

The coordinates of Point P

Solution:

Let the coordinates of P are (x,x)

Given that P(x,x) is equidistant to A (5,0) and  B (0,3)

So PA=PB

⇒ PA²=PB²

⇒(x-5)²+(x-0)²=(x-0)²+(x-3)²

⇒x²-10x+25+x²=x²+x²-6x+9

⇒-10x+6x=9-25

⇒-4x=-16

⇒    $x=\frac{-16}{-4} = 4$

Answer:

The coordinate of the desired point P are (4,4)

Formula used:

Distance between two pints A (x1,y1) and (x2,y2)

$d=\sqrt{(x_{1} -y_{1} )^{2} +{(x_{2} -y_{2} )^{2$