Question

the point whose abscissa is equal to its ordinate which is equidistant from A(-1,0) and B(0,5)​

Answer 1

Answer:

Point is ( 2 , 2)

Step-by-step explanation:

the point whose abscissa is equal to its ordinate which is equidistant from A(-1,0) and B(0,5)​

abscissa is equal to its ordinate

so let say point P is (  a , a)

This point is equidistant from A(-1,0) and B(0,5)​

=> |PA| = |PB|

=> PA² = PB²

PA² = (a + 1)² + a²

PB² = a² + (a - 5)²

Equating  both

(a + 1)² + a² = a² + (a - 5)²

=> (a + 1)² = (a - 5)²

=> a² + 1 + 2a = a² + 25 - 10a

=> 12a = 24

=> a = 2

Point is ( 2 , 2)

Answer 2

a round solid figure, or its surface, with every point on its surface equidistant from its centre.