Question

The points (1,6) (4,6) and (8,6) are collinear then the area of triangle is 0 sq unit

Answer 1

Solution :-

We know, that area of a triangle is

$\bf{\frac{1}{2}} \bf{\left[\begin{array}{ccc}x_1&y_1&1\\x_2&y_2&1\\x_3&y_3&1\end{array}\right]}$

i.e.

$\bf{\rightarrow\:\:\frac{1}{2}\: |x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)|$

If we substitute the values

We get,

$\bf{\rightarrow\:\:\frac{1}{2}\: |1(6-6)+4(6-6)+8(6-6)|$

$\bf{\rightarrow\:\:\frac{1}{2}\: |1(0)+4(0)+8(0)|$

$\bf{\rightarrow\:\:\frac{1}{2}\: |0+0+0|$

$\bf{\rightarrow\:\:\frac{1}{2}*0$

$\bf{\rightarrow\:\:\ 0$

∴ Hence, Area is zero

__________________________________

Thank you, please mark as brainliest!

$\bf{\rightarrow\:\:ANAGH\:\:$ :)