the points (1,7),(4,2) and (-1,-1) forms a triangle which is.. scalene,equaliteral,or isoceles
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let the vertices of the triangle be
A(1,7), B(4,2), C(-1,-1)
So,
AB = √(1-4)²+(7-2)² = √(-3)²+(5)² = √9+25 = √34
BC = √(4+1)²+(2+1)² = √(5)²+(3)² = √25+9 = √34
CA = √(-1-1)²+(-1-7)² = √(-2)²+(-8)² = √4+64 = √68
Here, AB = BC ≠ CA
⇒ ΔABC is an isosceles Δ.
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