Question

the points (-2,-1) (1,0) (4,3) and (1,2) are the vertices of a parallelogram taken in order. The point of intersection of its diagonals is
a) (-1,1)
b) (-2,2)
c) (1,1)
d) (2,2)

Answer 1

Step-by-step explanation:

Let A(-2, -1), B(1, 0), C(4, 3) and D(1, 2) are the vertices of a parallelogram. Let M be the midpoint of AC, then the coordinates of M are given :

((-2+4)/2,(-1+3)/2)

=> (1,1)

Let N be the midpoint of BD, then the coordinates of N are given:

((1+1)/2,(0+2)/2)

=> (1,1)

so answer is (1,1).