The points (2,4), (4,2), (7,1) are the vertices of which triangle and it's solution
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Answered by
3
Answer:
ANSWER
P(2,−4)Q(4,−2)R(7,1)
Check for option A
PQ=22
QR=32
RP=52
Not an equilateral Δ
Now, equation of line of PQ
(x−4)(1)=y+2
x−y=6
Satisfies point R
Hence PQR are collinear point.
Answered by
3
Answer:
scalen triangle
Step-by-step explanation:
- Let A=(2,4) B=(4,2) C=(7,1) AB= square root 2^2+(-2^2)= square root 4+4= square root 8 units
BC=square root 3^2+(-1^2)= square root 9+1= square root 10 units
CA=square root 5^2+(-3^2)= square root 25+9=square root 34 units NO SIDES ARE EQUAL
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