Question

the points (2,5),(3,3)and(k,1) lies in a straight line. find tge value of k​

Answer 1

Answer:

first find the gradient

x1 = 2

x2 = 3

y1 =5

y2 = 3

m = (y2 - y1) / (x2 -x1)

m = (3 - 5) / (3 - 2)

m= -2 / 1

m = -2

Next find the value of c

y = mx + c

5 = (-2*2) + c

5 = -4 + c

c = 9

then when y = 1

y = mx + c

1 = -2x + 9

-2x = -8

x = -8 / -2

x= 4

So k =4

done!

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