Question

. The points (-2,5) and (3,-5) are plotted in xy planes. Find the slope and y intercept of the line joining the points.

Answer 1

points are(-2,5) and (3,-5).

slope(m) has the formula as

m=(y2-y1)/(x2-x1).

Now x1 and y1 are -2 and 5.

And x2 and y2 is 3 and -5.

Hence,

Slope m-(-5-5)/(3-(-2))

m=-10/5 = -2

Now, putting the value of m in the equation of a straight line

y=mx +c

y= -2x +c

Putting the value of any point in the equation

Let (-2,5).

5=-2*-2+c

c= 5-4= 1

Hence, y intercept is 1.

If you would have taken the value of (3,-5) same value of c which is y intercept would have come.

Answer 2

Given:-

• The points (-2,5) and (3,-5) are plotted in xy planes.

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To find:-

• The slope and y intercept of the line joining the points.

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Solution:-

Let,

• the slope be m.

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According to the question,

⇛ m = 5 + 5/-2 -3

⇛ m = -2

⇛ y - 5 = -2(x + 2)

⇛ y - 5 = -2x - 4

⇛ y + 2x = 1

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Hence,

• Slope = -2
• y intercept = 1[(0,1)]